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# CS101 Assignment no 01 Spring 2013 Solution upload

Assignment No. 01
Semester: Spring 2013
Introduction to Computing-CS101

Total Marks: 20Due Date: 02-05-2013
Instructions:Please read the following instructions carefully before submitting assignment:

• You will submit your assignment before or on due date on VU-LMS.
• Assignment should be completed by your own efforts it should not be copied from internet, handouts or books.
• You should submit your MS Word File via assignment interface at VU-LMS.
• Assignment sent via Email will not be replied and accepted/graded in any case.
• If the submitted assignment does not open or file is corrupt, it will not be graded.
• You will submit solution only in MS Word File.

Objectives:

To understand the fundamental concepts of Binary Number Systems.

For any query about the assignment, contact at cs101@vu.edu.pk.

Assignment

Fill the empty columns for the following truth table where A, B and C are three binary inputs in the truth table.

 Inputs Output Output Output Output Output A B C (A´. B´)´ (A´+B)´ (B+C)´ (A. B)´⊕(B+C´) (A⊕ B). (B+C) 0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1

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# Idea Solution

 Inputs Output Output Output Output Output A B C (A´. B´)´ (A´+B)´ (B+C)´ (A. B)´⊕(B+C´) (A⊕ B). (B+C) 0 0 0 (1 . 1)’=0 (1+0)’=0 (0+0)’=1 1 0.0=0 0 0 1 (1 . 1)’=0 (1+0)’=0 (0+1)’=0 0 0.1=0 0 1 0 (1 . 0)’=1 (1+1)’=0 (1+0)’=0 0 1.1=1 0 1 1 (1 . 0)’=1 (1+1)’=0 (1+1)’=0 0 1.1=1 1 0 0 (0 . 1)’=1 (0+0)’=1 (0+0)’=1 1 1.0=0 1 0 1 (0 . 1)’=1 (0+0)’=1 (0+1)’=0 0 1.1=1 1 1 0 (0 . 0)’=1 (0+1)’=0 (1+0)’=0 0 0.1=0 1 1 1 (0 . 0)’=1 (0+1)’=0 (1+1)’=0 0 0.1=0

If you Found any error then pleas inform us via Comments

# Download The Attached File For Step By Step Solution

Click Here to download CS101 Assignment no 01 Step By Step Solution

### 5 comments

1. What is this ……………………………How can a 0 chang to 1 A =0 B=0 than 0*0=0 and 1+1=10 go to (Start) open calculator convert ur cal on Sci Binary than do that all on it ..

2. What is ((((((((((((( ‘ )))))))))) this coma

3. ok if thy are and or not Xnor operation then thy may be true